3X 2 X 3

3X 2 X 3. X2 −x −64x+ 23 = x− 37 − x +23 explanation: Kita uji setiap interval dengan mengambil salah satu nilai x dari tiga interval tersebut. (x −3)(x+2)4x+ 23 = x −3a + x+2b. How do you factor h(x) = x3 − 3×2 −x+ 3 ?

Factor using the rational roots test. So (x −1) is a factor. Use synthetic division to find the remaining factor.

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Use the power rule aman = am+n a m a n = a m + n to combine exponents. Factor by grouping and using the difference of squares identity to find: (3×2)3 ( 3 x 2) 3.

33(X2)3 3 3 ( X 2) 3.

First notice that substituting x = 1 results in x3 −3x + 2 = 0. (3×2)3 ( 3 x 2) 3. 3(x+2)=3x+6 equation is alway true rearrange:

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Apply the product rule to 3x 3 x.

Kesimpulan dari 3X 2 X 3.

(1 − 3x)/(2x − 2. If f(x) = 3x$^{2}$ + x$^{3}$logx, then f(x) is? Kita uji setiap interval dengan mengambil salah satu nilai x dari tiga interval tersebut.

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